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PHYS1112: Find the induced displacement current through the surface.?
A uniform electric field is oriented so that it makes a 60-degree angle with the normal to a 1 m^2 surface. The electric field is changing with respect to time by a rate of 6.0 V/m*us. Find the induced displacement current through the surface.
a. 27 uA
b. 46 uA
c. 53 uA
d. 0.59 uA
1 Answer
- NCSLv 76 days agoFavorite Answer
displacement current I = ε₀ * dΦ/dt
where ε₀ = 8.85e-12 C²/N·m²
and electric flux Φ = E*A*cosΘ
Since the area A and angle Θ aren't changing,
dΦ/dt = dE/dt * A*cosΘ = 6.0V/m·µs * 1m² * cos60º
dΦ/dt = 3.0 V·m/µs = 3.0 N·m² / C·µs = 3.0e6 N·m² / C·s
Then I = 8.85e-12 C²/N·m² * 3.0e6N·m²/C·s = 27 µA ◄ a
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Source(s): (35.7) here: http://teacher.pas.rochester.edu/phy122/lecture_no...
