Bullwinkle
f(x) = 5/x^2
Your values for f(x) when x is negative are NOT CORRECT...why do you thing the function evaluates as 'negative ?'
f(- 4) = 5 / (- 4)^2 = 5/16 = 0.3125
similarly for (x = - 4, - 3, - 2, - 1)...
As well, I don't agree with your rounding for f(- 3) nor f(3)...If you are displaying three decimals, how did you round ??
You need to see your teacher for help...squaring any real number ALWAYS results in a positive !!
EDIT: I forgot the MOST IMPORTANT COMMENT...when x = 0, the function is UNDEFINED !! NOT ZERO !! There is an asymptote at x = 0
?
When you square a negative number, the result is positive!
f(-4) = 0.3125
f(-3) = 0.555
f(-2) = 1.25
f(-1) = 5
the rest are ok