three consecutive numbers that add up to 187?

2015-05-28T13:37:40Z

two consecutive integers sum up to 187

Puzzling2015-05-28T13:41:50Z

In your update, you say *two* consecutive integers.

Let n be the first number.
Let n+1 be the second number.

The sum is 187:
n + n+1 = 187
2n + 1 = 187
2n = 186
n = 186/2
n = 93

Answer:
93 and 94

?2015-05-28T13:28:59Z

1 8 and 7

Krishnamurthy2015-05-29T02:13:08Z

n + (n + 1) = 187
2n + 1 = 187
2n = 186
n = 93
The numbers are 93 and 94..

Philip2015-05-30T04:42:06Z

187 is NOT divisible by 3. Therefore there exists no triplet of consecutive integers such that the sum is not
divisible by 3. Easy to prove: Put triplet = n-1, n, n+1. Then sum = 3n which IS divisible by 3.

just ask me2015-05-28T13:33:52Z

(x-1)+x+(x+1)=187
3x=187
x=62.33...
so the numbers are 61.33..., 62.33..., 63.33... I wouldn't call them consecutive though, they're not integers.
(Bear in mind that 187 isn't divisible by 3 because the sum of 187's digits is 1+8+7=16 which isn't divisible by 3).

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