solving using substitution method d=3c-1 d=5c+2?

d = 3c - 1
d = 5c + 2

Substituting the d in the first equation for the d in the second equation
3c - 1= 5c + 2

Subtract 3c from both sides
-1 = 2c + 2

Subtract 2 from both sides
-3 = 2c

Divide both sides by 2
-3/2 = c
c = -3/2 <-----

Substitute c = -3/2 in the first equation
d = 3(-3/2) - 1
d = -9/2 - 1
d = -9/2 - 2/2
d = -11/2 <-----



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