The perimeter of a rectangle is 44cm, and its area is 40cm2 (centimeter squared) Find the dimensions of the rectangle.?

Philip2015-06-05T19:05:47Z

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L + W = (1/2)44 = 22 so L = 22 - W..[1]. Now area = 40, ie., LW = 40, ie., W(22 - W)= 40, ie.,W^2 - 22W = - 40,
ie., (W-11)^2 =121-40 =81 =9^2 and W =11(+/-)9 =2 or 20. Clearly, (L , W) = (20 , 2) since L > W. [units=cm].

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The Me2015-06-05T18:49:12Z

The length is L, the width is W
2L+2W=44
LW=40
W=40/L
2L+2(40/L)=44
2L+80/L=44
2L^2+80=44L
L^2-22L+40=0
(L-2)(L-20)=0
L=2 or L=20
W=2 or W=20

The rectangle is 2 by 20

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