physics help please?

1. A man fills a balloon with .5 liters of air. He then puts the balloon into the oven and heats it to 204•C. The temperature outside the oven was 20•C.
- 1A - what is the new volume of the balloon?

- 1B - what gas law is used to solve this?

2. A hot air balloon descends from a pressure of 380 mm Hg to 760 mm Hg and at the high altitude has a volume of 1,000 cubic meters. The initial temperature is 50•C and drops to 25•C.

-2A - convert Celsius temperature to kelvin ( absolute temperature). what are the new temperatures?

- 2B - what would be the final hot air ballon volume?

- 2C - which has law should be used determine the unknown (the final volume)?


Answer choices
1A - A. 3L
B. .3L
C. 8L
D. .8L

1B. A. Boyle's law
B. Charles' law
C. combined gas law

2A. A. T1 = 323K, T2=298K
B. T1=298K, T2=323K
C. T1=200K, T2=75K
D. T1=82 degrees K, Tx=57K

2B. A. 461 m^3
B. 250 m^3
C. 541 m^3
D. 46.1 m^3

2C. A. P1 x V1 = P2
B. V1/T1 = V2/T2
C. P1/T1 = P2/T2
D. P1 x V1/T1 = P2 x V2/T2

Roger the Mole2015-07-01T15:05:46Z

1A.
(0.5 L) x (204 + 273) K / (20 + 273) K = 0.8 L
So answer D.

1B. B. Charles' law

2A.
50•C + 273 = 323 K
25•C + 273 = 298 K
So answer A.

2B.
(1000 m^3) x (298 K / 323 K) x (380 mm Hg / 760 mm Hg) = 461 m^3
So answer A.

2C. D. P1 x V1/T1 = P2 x V2/T2