Keith A
Favorite Answer
( (6y-3)-(y+2) ) / (5y)
= (5y - 5) / (5y)
= 5 (y - 1) / 5y
= (y - 1) / y -- also = 1 - 1/y
aman
6y-3-y-2/5y
5y-5/5y
5(y-1)/5y
y-1/y
Krishnamurthy
[(6y - 3) - (y + 2)] / 5y
= (5y - 5) / 5y
= (y - 1)/y
sombra
(6y-3-y-2):5y=
(5y-5):5y
5(y-1):5y=
(y-1):y