How many bromine atoms are present in 37.8 g of CH2Br2?
How many bromine atoms are present in 37.7 g of CH2Br2?
How many bromine atoms are present in 37.7 g of CH2Br2?
hcbiochem
37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2
4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms
?
17. Then again 17 is the answer to everything.