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caleb
caleb asked in Science & MathematicsChemistry · 5 years ago

How many bromine atoms are present in 37.8 g of CH2Br2?

Update:

How many bromine atoms are present in 37.7 g of CH2Br2?

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  • hcbiochem
    Lv 7
    5 years ago

    37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2

    4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms

  • Q The First Timelord
    5 years ago

    17. Then again 17 is the answer to everything.

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