Physics Help Please 2 part Best Answer! A small earthquake starts a lamppost vibrating back and forth. I have no idea where to even start?

A small earthquake starts a lamppost vibrating back and forth. The amplitude of the vibration of the top of the lamppost is 6.3 cm at the moment the quake stops, and 7.2 s later it is 2.0 cm .

Part A) What is the time constant for the damping of the oscillation?

Part B) What was the amplitude of the oscillation 3.6 s after the quake stopped?

NCS2016-12-05T16:38:37Z

Favorite Answer

A) I'd start with
A = A₀*e^(-t/τ)
which means that
ln(A/A₀) = -t/τ

ln(2.0/6.3) = - 7.2s / τ
τ = 6.28 s ◄

B) A = 6.3cm * e^(-3.6 / 6.28) = 3.5 cm ◄

Hope this helps!

10

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