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Physics Help Please 2 part Best Answer! A small earthquake starts a lamppost vibrating back and forth. I have no idea where to even start?
A small earthquake starts a lamppost vibrating back and forth. The amplitude of the vibration of the top of the lamppost is 6.3 cm at the moment the quake stops, and 7.2 s later it is 2.0 cm .
Part A) What is the time constant for the damping of the oscillation?
Part B) What was the amplitude of the oscillation 3.6 s after the quake stopped?
1 Answer
- NCSLv 74 years agoFavorite Answer
A) I'd start with
A = A₀*e^(-t/τ)
which means that
ln(A/A₀) = -t/τ
ln(2.0/6.3) = - 7.2s / τ
τ = 6.28 s ◄
B) A = 6.3cm * e^(-3.6 / 6.28) = 3.5 cm ◄
Hope this helps!
Source(s): Please revisit: /question/index?qid=20161...
