Physics HELP Please 3 parts for best answer! A 50-cm-long spring is suspended from the ceiling. A 210 g?

A 50-cm-long spring is suspended from the ceiling. A 210 g mass is connected to the end and held at rest with the spring unstretched. The mass is released and falls, stretching the spring by 28 cm before coming to rest at its lowest point. It then continues to oscillate vertically.

Part A) What is the spring constant? (k=___)

PartB) What is the amplitude of the oscillation (A=_____)

Part C) What is the frequency of the oscillation? (f=____)

?2016-12-06T14:04:15Z

Favorite Answer

A) k = 2*m*g/y = 2*0.210*9.8/0.28 = 14.7 N/m
B) A = 14 cm
C) f = (1/2π)*√[k/m] = 1.33 Hz

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