Physics please help Will give Best Answer Picture in details! Your car rides on springs, so it will have a natural frequency of oscillation?

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As the bumps are 13 feet apart the wavelength = 13 feet
V = f * lambda
f = V /lambda
But V must match the units of wavelength. So convert V to feet per second
V = 30 * 5280/3600 feet per sec
-> f = (30 * 5280/3600)/ 13 = 3.4 Hz

This is the frequency of the bumps on the road.
From the graph we can see that the frequency is around 2 Hz so one concludes that the frequency of the car is actually f/2 and each bump coincides with each SECOND bounce of the car.
ie the wavelength is actually 13/2

Now the only trouble is that if this was true then there should be a second peak at f = 3.4 Hz on the graph.
As this does not occur the graph appears to be inconsistent with the data of the question....Show more

v = 30*22/15 = 44 ft/sec
λ = 13 ft
f = v/λ = 3.38 Hz...Show more