((log^2)_25 to 125) - ((log^2)_25 to 5)?

Not quite sure of your notations...
but I figure it's
(log to the base 25 of 125) squared - (log to the base 25 of 5) squared
so:
(log_25(125))^2 - (log_25(5))^2 .... difference of squares factorisation
= (log_25(125) + log_25(5)) (log_25(125) - log_25(5))
= log_25(625) * log_25(25)
= 2log_25(25) * 1
= 2*1
= 2...Show more