log_0.1 to x=4log_0.1 to 3 - 2/3log_0.1 to 27+2log_0.1 to 6?

Sqdancefan2016-12-20T22:40:52Z

Taking the antilog, you have
.. x = 3^4/27^(2/3)*6^2
.. = 4*3^6/3^2
.. = 3^4/3^2*6^2
.. = 9*36
.. = 324

?2016-12-20T22:42:36Z

 
We say "log OF", not "log to"

log_0.1(x) = 4 log_0.1(3) − 2/3 log_0.1(27) + 2 log_0.1(6)
log_0.1(x) = log_0.1(3^4) − log_0.1(27^(2/3)) + log_0.1(6^2)
log_0.1(x) = log_0.1(81) − log_0.1(9) + log_0.1(36)
log_0.1(x) = log_0.1(81/9*36)
log_0.1(x) = log_0.1(324)

x = 324

?2016-12-20T22:34:11Z

Here's some symbols. Feel free to copy into a text doc and copy/paste in future:
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subscripts: ₀₁₂₃₄₅₆₇₈₉
∴∞ ∑®ºøπ«ß©∆˚Ω√∫µ≤≥÷ € ‰ Ø Å

Please rewrite your expression, and make sure to use enough (parens)