What is the volume percent of water in 14.8 M ammonium hydroxide?

mass percent is easy volume percent is not. I don't think you can calculate the volume percent. Ammonia is a gas and a weak base in solution - in solution it is still mostly NH3 though sometimes labelled NH4OH. You can't calculate a volume for NH4OH and ammonia does not stay as a gas. I would go with mass percent....Show more

Your question is easy to answer without knowing how much water is present in the original solution. You are simply doing a dilution calculation which uses the formula:
M1V1 = M2V2
(14.8 M) (V1) = 1.87 M (100 mL)
V1 = 12.6 mL

So, by taking 12.6 mL of the 14.8 M NH4OH solution and adding water to a final volume of 100 mL, the resulting solution will have a concentration of 1.87 M.

(As an aside, ammonium hydroxide is somewhat of a misnomer. It is just a solution of NH3 in water.)...Show more