If the plates are separated by 4.98 cm, what is the potential energy of an electron located at the negative plate?

The electric field between two parallel plates is 9.36 x 104 V/m. If the plates are separated by 4.98 cm, what is the potential energy of an electron located at the negative plate?


3.71 keV
4.67 keV
3.91 keV
5.71 keV

peterpan2017-06-13T19:10:03Z

Favorite Answer

V = E d
V = 9.36x10^4 * 4.98x10^-2
V = 4.67 keV

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