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If the plates are separated by 4.98 cm, what is the potential energy of an electron located at the negative plate?

The electric field between two parallel plates is 9.36 x 104 V/m. If the plates are separated by 4.98 cm, what is the potential energy of an electron located at the negative plate?

3.71 keV

4.67 keV

3.91 keV

5.71 keV

1 Answer

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  • 4 years ago
    Favorite Answer

    V = E d

    V = 9.36x10^4 * 4.98x10^-2

    V = 4.67 keV

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