Physics ASAP!? (6/7/8)?

A wheel starts from rest and rotates with constant angular acceleration to an angular

speed of 8.3 rad/s in 4.57 s.

Find the magnitude of the angular acceleration of the wheel in units of rad/s^2

angular acceleration α = ω/t = 8.3 rad/s / 4.57 sec = 1.82 rad/sec^2

Find the angle Θ in radians through which it rotates in this time in units of rad.

Θ = ω*t/2 = 8.3/2*4.57 = 18.6 rad

Bonus: at t = 0, a wheel rotating about a fixed axis at a constant angular deceleration of 0.3 rad/s^2 has an angular velocity of 3.6 rad/s and an angular position of 8.4 rad.

What is the angular position of the wheel

after 4 s? Answer in units of rad.

ω = 3.6 rad/sec 

ω' = ω-α*t = 3.6-0.3*4 = 2.4 rad/sec 

ΔΘ = (ω+ω')*t/2 = 6*2 = 12 rads

Θ' = Θ-ΔΘ = 8.4-12 = -3.6 rads