Find the equation of the line that contains the given points. P1(−1, 1), P2(4, 4) I got undefined?

slope = (4-1)/(4-(-1)) = 3/5
y - 1 = ⅗(x+1)
y = ⅗x+8/5...Show more

m = 3 / 5
y - 4 = (3/5) ( x - 4 )
y = (3/5) x - 12/5 + 20/5
y = (3/5) x + 8/5...Show more

(y - 1)/(4 - 1) = [x - (-1)]/[4 - (-1)].

(y - 1)/3 = (x + 1)/(4 + 1).

(y - 1)/3 = (x + 1)/5.

5(y - 1) = 3(x + 1).

5y - 5 = 3x + 3.

5y = 3x + 3 + 5.

5y = 3x + 8.


y = (3/5)x + 8/5 (Answer)....Show more

First, slope is rise/run . where rise is the change in the y coordinate and run is the change in the x coordinate

So the slope is (4 - 1)/(4 + 1) = 3/5

For any point (x,y) on the line
(y -1)/(x+1) = 3/5
use this to get the line equation
==> 5(y-1) = 3(x+1)
==> 5y - 5 = 3x + 3
==> 3x -5y = -8 (or 5y -3x = 8 or y = 3x/5 + 8/5)...Show more

y=3/5x+8/5
I used an on line calculator:
http://www.webmath.com/_answer.php...Show more