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Favorite Answer
for each thread, vertical force
Fy = 0.0034kg * 9.8m/s² = 0.03332 N
so the horizontal component is such that
tanΘ = Fx / Fy, or
Fx = Fy * tanΘ = 0.03332N * tan26º = 0.01625 N
the inter-charge distance
d = 2LsinΘ = 2 * 1m * sin26º = 0.877 m
electrostatic force
F = kq² / d²
so
q² = Fd² / k = 0.01625N * * (0.877m)² / 8.99e9N·m²/C² = 1.39e-12 C²
so
q = 1.2e-6 C = 1.2 µC
either both negative or both positive
to two significant digits
Hope this helps!