Physics question!?

for each thread, vertical force

Fy = 0.0034kg * 9.8m/s² = 0.03332 N

so the horizontal component is such that

tanΘ = Fx / Fy, or

Fx = Fy * tanΘ = 0.03332N * tan26º = 0.01625 N

the inter-charge distance

d = 2LsinΘ = 2 * 1m * sin26º = 0.877 m

electrostatic force

F = kq² / d²

so

q² = Fd² / k = 0.01625N * * (0.877m)² / 8.99e9N·m²/C² = 1.39e-12 C²

so

q = 1.2e-6 C = 1.2 µC

either both negative or both positive

to two significant digits

Hope this helps!