20/3.14) sin(2t)+(40\(3.14^2)cos(2t) = 7.5cos(2t-22) can someone please explain how?
The point of the excersise is to use the 7.5 cos(2t-122) to solve an eleectrical engineering problem. but my trig is rusty. Any help is appreciated.
The point of the excersise is to use the 7.5 cos(2t-122) to solve an eleectrical engineering problem. but my trig is rusty. Any help is appreciated.
alex
4.06 cos(2t)+6.37 sin(2t) = √(4.06^2+6.37^2)[cos(2t) cos(a)+sin(2t)sin(a)] , with a = tan^-1(6.37/4.06) = 1 rad
= 7.55 cos(2t - 1)