There are 2 green marbles, 3 red marbles, and 4 blue marbles in a bag. You will draw one, replace it and draw another.?
What is the probability that the 2 marbles you pick are the same color? What is the probability they will be different colors?
What is the probability that the 2 marbles you pick are the same color? What is the probability they will be different colors?
llaffer
Let's break this up into pieces.
Let's look at the green first.
The probability of drawing green is 2/9.
With replacement, the probability of drawing a green again is 2/9.
So the probability of both happening is the product of the individual probabilities, or:
(2/9)² = 4/81
Now let's look at the reds. Similar logic just slightly different numbers:
(3/9)² = 9/81 (didn't reduce here since we'll be adding fractions later so need the common denominator).
And finally the blues:
(4/9)² = 16/81
Now if we add them up we get the probability of both green OR both red OR both blue (aka, both the same color):
4/81 + 9/81 + 16/81 = 29/81 or approx 0.358 (rounded to 3DP)
Fuhr
Seven.