Find all solutions to the following equation:
2 sin x + 1 = 0
2 sin x + 1 = 0?

Question

Outlier · Accepted Answer

2 sin x + 1 = 0
2 sin x = -1
sin x = -0.5

Now arcsin (0.5) = pi/6

Since sin x is negative, the angle x is in the third or fourth quadrant, for one complete revolution.

That is, x = pi + pi/6 = 7pi/6
Or x = 2pi - pi/6 = 11pi/6

For all revolutions, all of the solutions are given by adding 2n pi, since 2pi is one complete revolution.

So answer is C.

? · Answer

2sin(x) + 1 = 0
2sin(x) = -1
sin(x) = -½
x = 1.5πk ± π/3, where k is an integer

Trending Questions