The specific heat capacity of water is 1.00 kcal/(kg · °C), and its latent heat of fusion is 79.8 kcal/kg.
(a) How much heat in kcal is required to raise the temperature of 0.510 kg of water from 0°C to 26.0°C?
(b) How much heat is required to first melt 0.510 kg of 0°C ice and then raise its temperature to 26.0°C?
NCS
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(a) Q = mcΔT
Q = 0.510kg * 1.00kcal/kg·ºC * 26.0º = 13.3 kcal
(b) Q' = mL + mcΔT
Q' = 0.510kg*79.8kcal/kg + 13.3kcal = 54.0 kcal
jacob s
An ice bag containing 0°C ice is much more effective in absorbing heat than one containing the same amount of 0°C water. The specific heat capacity of water is 1.00 kcal/(kg · °C), and its latent heat of fusion is 79.8 kcal/kg.
(a) How much heat in kcal is required to raise the temperature of 0.390 kg of water from 0°C to 26.0°C?
in kcal
(b) How much heat is required to first melt 0.510 kg of 0°C ice and then raise its temperature to 26.0°C?
in kcal
a) Q= mc(T0-Tf)
Q=0,51Kg*1.00 kcal/(kg · °C)* (26 C- 0 C)
Q= 13,26 kcal
b) Q= mL + mc(T0-Tf)
Q=0,51Kg*79.8 kcal/kg + 0,51Kg*1.00 kcal/(kg · °C)* (0 C- 26 C)
Q= 55,29 kcal -13,26 kcal= 40,698 kcal
Ender772
are we assuming pressure does not matter?