An ice bag containing 0°C ice is much more effective in absorbing heat than one containing the same amount of 0°C water. ?

(a) Q = mcΔT

Q = 0.510kg * 1.00kcal/kg·ºC * 26.0º = 13.3 kcal

(b) Q' = mL + mcΔT

Q' = 0.510kg*79.8kcal/kg + 13.3kcal = 54.0 kcal

An ice bag containing 0°C ice is much more effective in absorbing heat than one containing the same amount of 0°C water. The specific heat capacity of water is 1.00 kcal/(kg · °C), and its latent heat of fusion is 79.8 kcal/kg.

(a) How much heat in kcal is required to raise the temperature of 0.390 kg of water from 0°C to 26.0°C?

in kcal

(b) How much heat is required to first melt 0.510 kg of 0°C ice and then raise its temperature to 26.0°C?

in kcal

a) Q= mc(T0-Tf)

Q=0,51Kg*1.00 kcal/(kg · °C)* (26 C- 0 C)

Q= 13,26 kcal

b) Q= mL + mc(T0-Tf)

Q=0,51Kg*79.8 kcal/kg + 0,51Kg*1.00 kcal/(kg · °C)* (0 C- 26 C)

Q= 55,29 kcal -13,26 kcal= 40,698 kcal

are we assuming pressure does not matter?