MATH HELP PLEASE?
A bug moves along the curve y= 4-x^2/16. Distance is measured in feet. The bug's y-coordinate is decreasing at 20 ft/sec when it reaches the point (4, 3). How fast is its x-coordinate changing?
A bug moves along the curve y= 4-x^2/16. Distance is measured in feet. The bug's y-coordinate is decreasing at 20 ft/sec when it reaches the point (4, 3). How fast is its x-coordinate changing?
Wayne DeguMan
dy/dt = -(x/8).dx/dt
so, with dy/dt = -20 and x = 4 we have:
-20 = -(4/8).dx/dt
so, dx/dt = 40
Hence, the x-coordinate is increasing at 40 ft/sec
:)>
alex
Hint:
x=4 , y=3 , dy/dt = 20 ft/s
y= 4-(x^2/16)
find dx/dt
Amy
Calculate the slope of the curve at (4,3). That tells you how fast y is changing as x changes. Use that to convert the y-component of speed to the x-component.