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Sra
Sra asked in Science & MathematicsMathematics · 8 months ago

MATH HELP PLEASE?

A bug moves along the curve y= 4-x^2/16. Distance is measured in feet. The bug's y-coordinate is decreasing at 20 ft/sec when it reaches the point (4, 3). How fast is its x-coordinate changing?

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  • Wayne DeguMan
    Lv 7
    8 months ago

    dy/dt = -(x/8).dx/dt

    so, with dy/dt = -20 and x = 4 we have:

    -20 = -(4/8).dx/dt

    so, dx/dt = 40

    Hence, the x-coordinate is increasing at 40 ft/sec

    :)>

  • alex
    Lv 7
    8 months ago

    Hint:

    x=4 , y=3 , dy/dt = 20 ft/s

    y= 4-(x^2/16)

    find dx/dt

  • Amy
    Lv 7
    8 months ago

    Calculate the slope of the curve at (4,3). That tells you how fast y is changing as x changes. Use that to convert the y-component of speed to the x-component.

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