Captain Matticus, LandPiratesInc
Favorite Answer
u = e^(x/2)
du = (1/2) * e^(x/2) * dx
du / u^2 =>
(1/2) * e^(x/2) * dx / e^(x) =>
(1/2) * dx / e^(x/2)
u(x) = e^(x/2) is what you're looking for. Don't worry about the (1/2) bit in the numerator. That can be factored out of the integral.
Also, you can't have u = -e^(-u) as a substitution.
u = e^(x/2)
du = (1/2) * e^(x/2) * dx
Anonymous
Another homework cheater
ted s
multiply the integrand by e^x/e^x to get to du / u².....u = e^x