Physics help needed!?

A wheel of diameter 85 cm spins at a rate such that a point on the rim of the wheel has an acceleration of 45 m/s^2. How many rotations does the wheel make in 1.0 min?

billrussell422020-12-15T00:59:53Z

Favorite Answer

45 m/s² = ω²r = ω²(85/2)
ω = 1.029 rad/s
1.029 rad/s x 2π rad/rev x 60s/min = 388 rev/min
388 rev/min x 1 min = 388 rev



Centripetal acceleration isa = Vdθ/dt = ω²r = Vω = V²/r   V is the tangental velocity in m/s   r is radius of circle in meters   ω is angular velocity in radians/sec = v/r   a is in m/s²