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Physics help needed!?
A wheel of diameter 85 cm spins at a rate such that a point on the rim of the wheel has an acceleration of 45 m/s^2. How many rotations does the wheel make in 1.0 min?
1 Answer
- billrussell42Lv 74 months agoFavorite Answer
45 m/s² = ω²r = ω²(85/2)
ω = 1.029 rad/s
1.029 rad/s x 2π rad/rev x 60s/min = 388 rev/min
388 rev/min x 1 min = 388 rev
Centripetal acceleration isa = Vdθ/dt = ω²r = Vω = V²/r V is the tangental velocity in m/s r is radius of circle in meters ω is angular velocity in radians/sec = v/r a is in m/s²