Bryce
Favorite Answer
a. v²/d= GMs/d²; v²= GMs/d; Ms= v²*d/G
Ms= [2π*4.82*10^11/(422*24*3600)]² * 4.82*10^11 / 6.67*10^-11
= 4.99*10^31 kg
b. Gbh/Gs= 1.99/30² / 4.99/(1.53*10^8)²≈ 1.04*10^13
The black hole has a surface gravitational force 10 trillion times greater than the star!
Anonymous
Do not use Kepler's law to solve.