As shown in the figure, a circuit consists of an emf source with V = 20.0 V and six resistors.Physics will give fave ans.?

Question

As shown in the figure, a circuit consists of an emf source with V = 20.0 V and six resistors. Resistors R1 = 5.00 Ω and R2 = 10.00 Ω are connected in series. Resistors R3 = 5.00 Ω and R4 = 5.00 Ω are connected in parallel and are in series with R1 and R2. Resistors R5 = 2.00 Ω and R6 = 2.00 Ω are connected in parallel and are also in series with R1 and R2.

What is the potential drop across each resistor?

How much current flows through each resistor?

What is the potential drop across each resistor?

How much current flows through each resistor?

Philomel · Accepted Answer

R                E               I
1                5.405v      1.081A
2                2.162v      1.081A
3&4            2.7.3v        .541Aea
5&6            1.081v       .541Aea

oubaas · Answer

R34 = R3//R4 = 5*5/(5+5) = 25/10 = 2.5 ohm
R56 = R5//R6 = 2*2/(2+2) = 4/4 = 1.0 ohm 
Req = R1+R2+R34+R56 = 5+10+2.5+1.0 = 18.5 ohm 
I = V/Req =  40/37 A
V1 = R1*I = 5*40/37 = 200/37 of V
V2 = R2*I = 10*40/37 = 400/37 of V
V34 = R34*I =  2.5*40/37 = 100/37 of V 
V56 = R56*I = 1.0*40/37 = 40/37 of V 
ΣV = V1+V2+V34+V56 = 740/37 = 20 V ....it works

az_lender · Answer

Equivalent resistance of R3||R4 is 2.50 ohms.
Equivalent resistance of R5||R6 is 1.00 ohms.
Equivalent resistance of the whole circuit is
5 + 10 + 2.5 + 1 = 18.5 ohms.
Current in R1 and R2 is (20V/18.5ohm) = 1.08 A.
Current in each of the other resistors is half of that, 540 mA.

As shown in the figure, a circuit consists of an emf source with V = 20.0 V and six resistors.Physics will give fave ans.?

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