9th grade math help if you can!?
Find the base of a triangle with a height of (3x^5y^3z^9)^2 and an area of 45x^12y^8z.
(A=1/2 bh)
Find the base of a triangle with a height of (3x^5y^3z^9)^2 and an area of 45x^12y^8z.
(A=1/2 bh)
?
Favorite Answer
See below for work and solution.
cmcsafe
Base =2*A/h = 2(45x^12y^8z)/(9x^10y^6z^18) =
= (90x^12*2y^8*z)/(9*x^10*y^6*z^18) =
= 10*x^(12-10)*2*y(8-6) /z^(18-1) =
= 10*x^2y^2 / z^17