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9th grade math help if you can!?

Find the base of a triangle with a height of (3x^5y^3z^9)^2 and an area of 45x^12y^8z.

(A=1/2 bh)

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  • ?
    Lv 7
    1 month ago
    Favorite Answer

    See below for work and solution.

    Attachment image
  • 1 month ago

    Base =2*A/h = 2(45x^12y^8z)/(9x^10y^6z^18) = 

    = (90x^12*2y^8*z)/(9*x^10*y^6*z^18) = 

    = 10*x^(12-10)*2*y(8-6) /z^(18-1) =

    = 10*x^2y^2 / z^17

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