Verify the given equation:?
sin(x)(1+cot^2 x) = csc(x)
sin(x)(1+cot^2 x) = csc(x)
Raymond
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The trick is to use identities, and then simplify whatever cancels out, to show that one side becomes the other.
For example, csc(x) = 1/sin(x), and
cot(x) = cos(x)/sin(x)
There are many routes you can use.
For this example, let's begin inside th bracket.
change cot^2(x) = cos^2(x) / sin^2(x)
(1 + cot^2(x)) becomes
(1 + cos^2(x) / sin^2(x))
Put all this bracket under the common denominator sin^2(x)
( sin^2(x)/sin^2(x) + cos^2(x)/sin^2(x) )
pull out the common denominator sin^2(x0
(it divides the whole bracket)
(sin^2(x) + cos^2(x))/sin^2(x)
The numerator is a famous identity, where sin^2 + cos^2 = 1
We have reduced the bracket to
1/sin^2(x)
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Let's now rewrite the entire equation using this substitution
sin(x) (1/sin^2(x)) = csc(x)
one sine below is cancelled by the sine above, leaving
1/sin(x) = csc(x)
which is the definition of a csc = 1/sin
?
https://www.wolframalpha.com/input/?i=sin%28x%29%281%2Bcot%5E2+x%29+%3D+csc%28x%29