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Question

(This is the only equation that I did not get correct)

The function h(a)=0.9(200−a) is used to calculate the handicap for a bowler (a bowling handicap is a percentage of the difference between your average and a basis average). In the function h(a)=0.9(200−a) , a bowler’s average a is used to determine their handicap h. How can we undo this original function to express a new function that tells us a bowler’s average a based on their handicap h.

What would be the inverse function? I tried 10 different answers. None were right.

? · Accepted Answer

h = 0.9(200 - a)

or, h = 9(200 - a)/10

Here, we have h in terms of a

We require a in terms of h

so, 10h = 9(200 - a)

Then, 200 - a = 10h/9

or, a = 200 - (10h/9)

Using a common denominator of 9 we can say:

a = (1800 - 10h)/9

:)>

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