The Ksp of Mercury (I) chloride is 1.20E-18. ?

Calculate the...
1) molar solubility (M)
2) concentration of Mercury (I) ion (M)
3)concentration of chloride ion (M)

Roger the Mole2021-04-07T21:20:26Z

HgCl → Hg{+} + Cl{-}  [balanced as written]

Ksp = [Hg+] * [Cl-] = 1.20 x 10^-18

2)
[Hg+] = √ (1.20 x 10^-18) = 1.10 x 10^-9 M

3)
[Cl-] = [Hg+] = 1.10 x 10^-9 M

1)
[HgCl] = [Hg+] = 1.10 x 10^-9 M

hcbiochem2021-04-07T21:13:35Z

Mercury(I) chloride has the formula Hg2Cl2.
Equilibrium: Hg2Cl2(s) <--> Hg22+(aq) + 2 Cl-(aq)
Ksp = [Hg22+][Cl-]^2 = 1.20X10^-18

1) and 2) Let x = molar solubility = [Hg22+], and from the stoichiometry, [Cl-] = 2x. Then,

1.20X10^-18 = x (2x)^2 = 4x^3
x = 6.69X10^-7 M = molar solubility = [Hg22+]

3) [Cl-] = 2x = 1.34X10^-6 M