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Tiffany
Tiffany asked in Science & MathematicsChemistry · 1 day ago

The Ksp of Mercury (I) chloride is 1.20E-18. ?

Calculate the...

1) molar solubility (M)

2) concentration of Mercury (I) ion (M)

3)concentration of chloride ion (M)

2 Answers

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  • Roger the Mole
    Lv 7
    24 hours ago

    HgCl → Hg{+} + Cl{-}  [balanced as written]

    Ksp = [Hg+] * [Cl-] = 1.20 x 10^-18

    2)

    [Hg+] = √ (1.20 x 10^-18) = 1.10 x 10^-9 M

    3)

    [Cl-] = [Hg+] = 1.10 x 10^-9 M

    1)

    [HgCl] = [Hg+] = 1.10 x 10^-9 M

  • hcbiochem
    Lv 7
    24 hours ago

    Mercury(I) chloride has the formula Hg2Cl2.

    Equilibrium: Hg2Cl2(s) <--> Hg22+(aq) + 2 Cl-(aq)

    Ksp = [Hg22+][Cl-]^2 = 1.20X10^-18

    1) and 2) Let x = molar solubility = [Hg22+], and from the stoichiometry, [Cl-] = 2x. Then,

    1.20X10^-18 = x (2x)^2 = 4x^3

    x = 6.69X10^-7 M = molar solubility = [Hg22+]

    3) [Cl-] = 2x = 1.34X10^-6 M

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