Practice Problem Physics ?

A particle with a charge of +3.2 x 10-18 C moves in a straight line at a constant velocity of 4.0 x 103 m/s to the right through a region of uniform magnetic field and uniform electric field. The uniform electric field has a magnitude of 0.25 N/C and points vertically up. No deflection from the particle’s straight path is observed. Ignore the impact of Earth’s magnetic field and Earth’s gravitational field on this particle.

1. force field diagram
2. sketch physical situation.
3. magnitude and direction
4. evaluate

NCS2021-04-08T02:52:08Z

Without the magnetic field, the electric field would force the charged particle upward. Therefore the magnetic field must point out of the page. For the two forces to balance,
q*E = qvB → → B = E / v

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