Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Practice Problem Physics ?

A particle with a charge of +3.2 x 10-18 C moves in a straight line at a constant velocity of 4.0 x 103 m/s to the right through a region of uniform magnetic field and uniform electric field. The uniform electric field has a magnitude of 0.25 N/C and points vertically up. No deflection from the particle’s straight path is observed. Ignore the impact of Earth’s magnetic field and Earth’s gravitational field on this particle.

1. force field diagram

2. sketch physical situation.

3. magnitude and direction

4. evaluate

1 Answer

Relevance
  • NCS
    Lv 7
    21 hours ago

    Without the magnetic field, the electric field would force the charged particle upward. Therefore the magnetic field must point out of the page. For the two forces to balance,

    q*E = qvB → → B = E / v

Still have questions? Get your answers by asking now.