trig identities help?

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// Note that sin² θ + cos² θ = 1
//            so sin² θ = 1 - cos² θ ....................[1]
// Also, 1 + cot² θ = csc² θ = 1/sin² θ ..........[2]
// Therefore,
(1 - cos² θ)(1 + cot² θ) = (sin² θ)(1/sin² θ) = 1 .........ANS...Show more