Given A at (-2,1) and B at (3, 4), what is the magnitude of vector AB?
a. √34
b. <5,3>
c. √30
d. √8
a. √34
b. <5,3>
c. √30
d. √8
Puzzling
Favorite Answer
Take the component differences first:
3 - (-2) = 5
4 - 1 = 3
So you are looking for the magnitude of vector <5, 3>
Finding the magnitude is just like finding the hypotenuse of a triangle with legs of 5 and 3.
5² + 3² = ||AB||²
25 + 9 = ||AB||²
||AB||² = 34
||AB|| = √34
Or you can use the formula:
||AB|| = √(5² + 3²)
||AB|| = √34
Answer:a. √34