oldschool
Favorite Answer
Model the weight = 200 vertically down at the midpoint of the beam.
Balance the torques:
The component of tension T perpendicular to the beam * L = Clockwise Torque
The component of W = 200N perpendicular to the beam * L/2 = CCW Torque
T*sin50 *L = 200*cos50 * L/2
T*sin50 = 100*cos50
T*tan50 = 100
T = 100/Tan50 = 83.9N <<<<<
billrussell42
what rope? strange drawing...
what weight?
it also shows a 90º corner as 50º ??