Riddle -- What's wrong with the proof that 1 = 2?

Well,

a^2 = ab

so

a^2 - ab = ab - ab = 0

So if you replace (a^2 - ab) with 0, you get

2(0) = 1(0)

You can't divide out the zeros, because 2/0 is undefined, so that's where the flaw is.

The problerm is that multiplying both area by technique of [(a million)^a million/2]*[(-a million)^a million/2](a million)^a million/2]*[(-a million)^a million/2[bdf722e19fdc8041b560576b4b7cbdf722e19fdc8041b560576b4b7c](a million)^a million/2]*[(-a million)^a million/2 between the perimeters ends with a nil as a factorbdf722e19fdc8041b560576b4b7cbdf722e19fdc8041b560576b4b7cbdf722e19fdc8041b560576b4b7c bdf722e19fdc8041b560576b4b7csame occurs on the single belowbdf722e19fdc8041b560576b4b7c in view that if m=nbdf722e19fdc8041b560576b4b7c then nbdf722e19fdc8041b560576b4b7cm=bdf722e19fdc8041b560576b4b7cbdf722e19fdc8041b560576b4b7c and that may´t keep the equationbdf722e19fdc8041b560576b4b7c I said one betterbdf722e19fdc8041b560576b4b7c yet extra basic to debunk demonstrating (a million)^a million/2]*[(-a million)^a million/2=(a million)^a million/2]*[(-a million)^a million/2 bdf722e19fdc8041b560576b4b7c3 = 4bdf722e19fdc8041b560576b4b7c6 bdf722e19fdc8041b560576b4b7c3bdf722e19fdc8041b560576b4b7c 9bdf722e19fdc8041b560576b4b7c4 = 4bdf722e19fdc8041b560576b4b7c6bdf722e19fdc8041b560576b4b7c 9bdf722e19fdc8041b560576b4b7c4 in view that 9bdf722e19fdc8041b560576b4b7c4 = squaredbdf722e19fdc8041b560576b4b7c3bdf722e19fdc8041b560576b4b7c which I´ll denote sqbdf722e19fdc8041b560576b4b7c3bdf722e19fdc8041b560576b4b7c bdf722e19fdc8041b560576b4b7c3bdf722e19fdc8041b560576b4b7csqbdf722e19fdc8041b560576b4b7c3bdf722e19fdc8041b560576b4b7c = 4bdf722e19fdc8041b560576b4b7c6bdf722e19fdc8041b560576b4b7csqbdf722e19fdc8041b560576b4b7c3bdf722e19fdc8041b560576b4b7c Factorize: sqbdf722e19fdc8041b560576b4b7cabdf722e19fdc8041b560576b4b7c (a million)^a million/2]*[(-a million)^a million/2 bdf722e19fdc8041b560576b4b7cab (a million)^a million/2]*[(-a million)^a million/2 sqbdf722e19fdc8041b560576b4b7cbbdf722e19fdc8041b560576b4b7c = squarebdf722e19fdc8041b560576b4b7cabdf722e19fdc8041b560576b4b7cbbdf722e19fdc8041b560576b4b7c sqbdf722e19fdc8041b560576b4b7c3bdf722e19fdc8041b560576b4b7c = sqbdf722e19fdc8041b560576b4b7c3bdf722e19fdc8041b560576b4b7c Get rooted andbdf722e19fdc8041b560576b4b7cbdf722e19fdc8041b560576b4b7cbdf722e19fdc8041b560576b4b7c bdf722e19fdc8041b560576b4b7c3bdf722e19fdc8041b560576b4b7c = bdf722e19fdc8041b560576b4b7c3bdf722e19fdc8041b560576b4b7c (a million)^a million/2]*[(-a million)^a million/2=(a million)^a million/2]*[(-a million)^a million/2

a = b

a^2 = ab

by adding both sides wth a^2

a^2 + a^2 = a^2 + ab

2a^2 = a^2 + ab

buy subtratcing both sides wth 2ab

2a^2 -2ab= (a^2 + ab)- 2ab

2(a^2 - ab)=a^2-ab

2=1

===

2a^2 = a^2 + ab this is where the formula is flawed.

I a=6 the b=6 because a=b

therefore 2a^2 = (2*6)^2 which = 144

and a^2 + ab = 6^2 + (6*6) which = 72

since a=b then a^2-ab=0 so on the equation 2(a^2 - ab) = 1(a^2 - ab)

it yields 2*0=1*0 which then becomes 0=0, so therefore 2=1 is invalid because you r trying to divide by zero: you took this equation 2(a^2-ab) = 1(a^2-ab) and made this equation: 2=1*(a^2-ab)/(a^2-ab) which then becomes:

2=1*(a^2-ab)/0 which is illegal operation division by zero.

Therefore, 2=1 is invalid equation because to be valid it is assumed that a is not equal to b.

Line 3 says a^2+a^2

Then on line four that is represented as 2a^2. That is not correct.

That is like saying that 3^2+3^2 = 6^2

or 9+9 = 36

Thats one problem

Nice question though

from the second last part, if you use your assumption that a=b then you cannot divide both sides by a^2 - ab, cos thats basically a^2-a^2=0. not allowed to divide by zero

goat boy. a squared plus a squared is 2 a squared. kind of basic, and correct.

one apple and one apple is, wait for it, 2 APPLES

1 can never be equals to 2 even if a=b.

1 doesnt equal 2.

:)

2(a2-ab) does not equal 1(a2-ab)