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Can anyone solve this? (A walk-through would be appreciated.)?
lim as x-->0 (ln(30/x)/ln(2))
4 Answers
- 2 decades agoFavorite Answer
First, use the identities for logarithms to simplify this. When you do, you get ln(30/x) = ln30 - ln x. Now, divide each of those terms by ln2 and you get ln30/ln2 - lnx/ln2. Now, take the limit as x->0. As x goes to zero from the right (the left hand limit does not exist), ln goes to minus infinity.
- 2 decades ago
First,
lim x-->0 (ln30-lnx)/ln 2
simply put x=0,
=ln30/ln2,now solve it!!
U can also apply L-Hospital rule but that will not give perfect answer.
- 2 decades ago
first look 30/x as x approaches 0....which will be infinity.
ln(infinity) is infinity, and infinity divided by anything is still infinity.
So the the answer is infinity...