Mr. "X" brought some flowers to perform "PUJA". he went to temple Lord Siva.?

Lets say he bought x flowers and at each temple he used y flowers

so, at first temple the flowers became 5x and he used y

so, he went to next temple with 5x - y flowers

They became 10 times and he used y flowers again

so he went to third temple with [10(5x - y) - y] flowers

they became 20 times and he used them all. So this is equal to y

so,

20 [10(5x - y) - y] = y

solve and u get

1000x = 221y

Now u have infinite solutions to this...

x = 221n

y = 1000n

Minimum numbers are

he bought 221 flowers and used 1000 flowers each time

other possibilties are 442 flowers bought and used 2000 flowers and so on...

He took 221 flowers to siva's temple .It multiplied five times to become 1105 flowers . He performed puj with 1000 flowers . took 105 flowers to vishnu's temple . It mutiplied ten times to 1050 flowers . He did puja with 1000 flowers there. He had 50 flowers left eith him. Took them to lakshmi's temple . They they increased by 20 times to 1000 flowers and he did puja with all the 1000 flowers and had none left on hand .He bought 221 flowers and used 1000 flowers for puja in each temple .Pose this problem to elementary school boys.

A minimum amout shows;- 221.

ie. a person brings 221 floweres and uses it for pooja with 1000 flower in each shrine.

(221*5) = 1105-1000=(105*10)=1050-1000=(50*20)=1000

any point on the graph of 1000x-221y=0 will be a correct ans(if the values are non-zero +ve integers)- where x represents the number of flowers taken and y represents the number of flower used in each temple.

he brought 221 flowers

and used 1000 at each temple

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