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What is the Differential of F(x)= 4995/(1+.12COS(x))?
5 Answers
- 1 decade agoFavorite Answer
f'(x) = 4995 * -1 * (1+.12COS(x))^-2 * 0.12 * -sin(x)
= 599.4 * (1+0.12cos(x))^-2 * sin(x)
- steiner1745Lv 71 decade ago
Since the numerator is constant we can use the
reciprocal rule. Also, the differential, dy, is
the derivative of the function times dx.
So
dy = -4995*(-.12 sin x)/(1 + .12 cos x) ^2 dx.
- 1 decade ago
well you can pull the 4995 out because its a constant
then you have 1/(1+.12cos(x)) .
the derivative of that is
-(.12sin(x))/((1+.12cos(x))^2)
final answer= {-4995*.12sin(x)}/[{1+.12cos(x)}]^2
- MarikoLv 41 decade ago
F(x)= 4995/(1+.12 cos x)
F'(x)= [(1+.12 cos x)*0 - 4995*(.12(-sin x))]/(1+.12 cos x)²
F'(x)= (599.4 sin x)/(1+.12 cos x)²
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- Anonymous1 decade ago
wow wow :O thats like the mostf*@#ed up peoce of maths i have ever seen but i ma take a guess and say 2
