algebra 2 problem ? plz help me!!!!?

IN SLOPE INTERCEPT FORM

y = 7/8 x - 8

http://www.pen.k12.va.us/Div/Winchester/jhhs/math/...

This is a graph... Put it in PAINT and figure out slope and y intercept.

PS please award best answer

If you mean that you want a line that passes through (7,-3) and perpendicular to y= -8 then:

First, for a line to be perpendicular to y = -8, the line would have to be a straight line in the form of x = something. That is the definition of a perpendicular line.

Second, for that perpendicular line to pass through (7,3), then x = 7. Again, this is purely definition.

y=-8 is a straight line parrallel to the x axis, so to be perpendicular to it, your line must be paralell to the y axis.

You don't actually know what you just said means, though, do you? It isn't a problem you solve using steps, it's a problem you solve by drawing a graph and looking at it.

(I seem to be telling lots of people to draw graphs these days, maybe there's something to that...)

(7, -3 ) is your (x, y) meaning x = 7 y = -3

first one, minus 0.9 from itself and from -a million.5 youll get 0.8x= ____ <-the version of -a million.5-0.9 then divide via 0.8 from the two factors to cancel out the 0.8 x= regardless of the version of -a million.5-0.9 / 0.8 2d one.. 6(x) = 6x+ 6(a million.37)=5x .. 6x+7.37=5x minus 6 x from the two factors 7.37=-x divide via -1x on the two factors x=-7.37